Basketball One-on-One : Kattis Solution in C++

#include<bits/stdc++.h>
using namespace std;
int main(int argc, char const *argv[]){
string n;
cin >> n;
int len = n.length();
int scoreA = 0,scoreB = 0;
for (int i = 0; i < len; i+=2) {
if(n[i] == 'A'){
int score = n[i+1] - '0';
scoreA += score;
}else if(n[i] == 'B'){
int score = n[i+1] - '0';
scoreB += score;
}
}
(scoreA > scoreB)
? cout << 'A'
: cout << 'B';
return 0;
}
question Link : https://open.kattis.com/problems/basketballoneonone

Comments

Post a Comment

Popular posts from this blog

Kattis Solution to Reverse Binary in C++

Image
#include<bits/stdc++.h> using namespace std; // using namespace std::chrono; int main(int argc, char const *argv[]) {     int n,i=0,t;     cin >> n;       vector<int>v;       // auto start = high_resolution_clock::now();     while(true){         t = n % 2;         v.push_back(t);         n = n / 2;         if(n == 0 ) break;         i++;     }     // auto stop = high_resolution_clock::now();     // auto duration = duration_cast<microseconds>(stop-start);     // cout << duration.count()<<endl;       reverse(v.begin(),v.end());     int index = 0,sum = 0;     for(auto b : v){         if(b == 1){             sum+=pow(2,index);     ...
Read more

Kattis Solution to Odd Man out In cpp

Image
#include <bits/stdc++.h> using namespace std ; int main ( int argc , char const * argv [ ]) { int n ; cin >> n ; for ( int i = 0 ; i < n ; ++ i ) { int t ; cin >> t ; set < int > s ; for ( int j = 0 ; j < t ; ++ j ) { int k ; cin >> k ; if ( s . count ( k )) { s . erase ( k ) ; } else { s . insert ( k ) ; } } cout << " Case # " << i +1 << " : " << * s . begin ( ) << " \n " ; } }
Read more